We have come to know that many students find it really difficult to calculate their aggregate score and their cut off mark and it really isn’t their fault as calculating cut off marks varies for different institutions.
On this note, we have made it easy for you by giving you step by step procedure on how to calculate Oyo State Technical University aggregate score, but before this, we are going to tell you what aggregate and Post UTME Score means and what things are to be considered before calculating the aggregate score.
WHAT IS AGGREGATE SCORE
That means the candidate must get at least 50 Questions Correctly. The aggregate score will be used to determine the cut-off point for admission into each of the programmes. Cut-off points for each course will be determined by the performance of all the candidates who applied for the course.
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WHAT IS POST UTME SCORE
After every UTME exercise, a particular mark is set out by the exam body {e.g 120}. This mark is a score a candidate must have or cross, to qualify him or her to sit for the chosen school’s POST UTME exercise. This said mark is announced to all school’s to enable them decide the number of candidates they will admit.
After the school’s decision, they announce a particular mark which must not be lower than the mark the UTME body fixed. Any candidate who cross the mark set by the UTME body and did not reach the chosen school’s mark, is NEVER eligible to sit for the school’s POST UTME.
This mark or score set by the school admission board is known as SCHOOL’S CUT OFF MARK.
TECH-U Departmental Cut Off Mark
Although the current general UTME Cut off Mark for TECH-U is 180, each department has its specifications.
Meanwhile, TECH-U also has supplementary forms for candidates who did not meet the minimum cut off point for their department.
Candidates are expected to have at least 5 Credits in their WASSCE or NECO Results.
Below are courses offered in the University as well as their cut off marks;
- 220 – 240 – Medicine (O’ Level result with one sitting only) and Nursing
- 200 – Mass Communication, Common Law, Pharmacy, Anatomy, Physiology
3.190 – Computer Science, English Language, Biochemistry, Microbiology, Geology, all engineering courses except Agricultural and Biosystem Engineering.
- 180 – All other courses
How To Calculate TECH-U Post UTME Aggregate Score
For example, in order to calculate your TECH-U Post UTME aggregate score, the formula purportedly adopted by the institution is the summing up of your UTME (JAMB) SCORE divided by 8 and your POST UTME SCORE divided by Your Jamb score is allocated 50%, Your O’level is 20% and your post-ume is 30%.
1. Considering JAMB Score:
Maximum score under JAMB is 400.To prorate to 50% your Jamb score will be divided by 8 (400/50
2. Considering O’level (WAEC, NECO, GCE or NABTEB):
O level is calculated using the 5 core subjects(core to the course you wish to study as decided by the University) as follows:
- A1 – 6 points
- B2 – 5 points
- B3 – 4 points
- C4 – 3 points
- C5 – 2 points
- C6 – 1 points
And maximum is 30 points. The total points is then prorated to 20 through multiplication by 2/3.
3. Considering POST-UTME:
Here is the score many candidates seem to find rather confusing. Some complain of having a higher score in the POST-UTME than university cut-off points without being admitted. But what they must understand is that even if they score 100% in that exam it amounts only to 30% of the cut-off point. So their Post -Utme score is usually prorated to 30 marks using 0.3 as the multiplier
Example: If a candidate had 202 in Jamb and his O level goes Like this: Maths-B3, Chemistry-C4, Biology- B2, English- C5, Physics-C6, Economic-B3, Geography-A1 and had 58% in the post utme. The he can calculate his composite, by following the format below:
Jamb score divided by 8 i.e 202/8=25.25
For the O level, only 5 subjects (math, English, chemistry, biology, and physics) are needed. There he has Math – B3 – 4 points, English – C5 – 2 point,Chemistry – C4 – 3 points,Biology – B2 – 5 points, Physics – C6 – 1 point Total gross points for O level= 4+2+3+5+1=15. This score is then multiplied by 2/3 i.e 15 x 2/3=10. His post utme score is allocated 30% and is multiplied by
0.3. i.e 58 x 0.3=17.4
Therefore, the candidates’ composite is the sum of these 3 scores i.e Jamb+O’level+post utme. That is 25.25+10+17.4=5 2.65 Hence, the candidate’s composite is 52.65.
Now note the 5-point gap between the composite total and what he scored in the post-utme. That 5-point gap may result in not being granted admission! Okay?
Pls NOTE that 100% used above may be equivalent to 100,200 or 400 marks in different universities
Alternatively you can follow this Example 2 to know your TECH-U Post UTME aggregate score and chances of Admission:
Example 2:
If Tina scored 290 in UTME (JAMB) and went on to score 70 in POST UTME, Tina’s aggregate score will be calculated as follows:
UTME Score = 290/8 =36.25
Post UTME Score = 70/2 =35
Tina’s Aggregate Score is =36.25 + 35 =71.25%
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